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a
Square planar
b
Pyramidal
c
Tetrahedral
d
Octahedral
answer is A.
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Detailed Solution
[Pt(NH3)2Cl2] O.S. of Pt+2; electronic configuration of Pt+2=[Xe]4f145d8. Ligand NH3 results in pairing of d electrons leaving one d orbital empty therefore hybridisation is dsp2 square planar