The Gibbs energy for the decomposition of Al2O3 at 500oC is as follows 23Al2O3→43Al+O2 ΔrG=+966 kJ mol−1The potential difference needed for electrolytic reduction of Al2O3 at 500oC is at least
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a
4.5 V
b
3.0 V
c
2.5 V
d
5.0 V
answer is C.
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Detailed Solution
23Al2O3→43Al+O2Thus, 23×3(O2−)i.e., 2O2−→O2+4e−[∵ n=4]ΔG=+966 kJ mol−1=966×103 J mol−1ΔG=−nFEcell966×103=−4×96500×EcellEcell=2.5 V