Give the correct of initials T or F for following statements. Use T if statement is true and F if it is false.(I) $$Co(IIl)$$ is stabilised in presence of weak field ligands, while $$Co(II)$$ is stabilised in presence of strong field ligand.(II) Four coordinated complexes of $$Pd(II)$$ and $$Pt(II)$$ are diamagnetic and square planar.(III) $$Ni(CN)44$$− ion and $$Ni(CO)4$$ are diamagnetic tetrahedral and square planar respectively.(Iy) $$Ni2+$$ ion does not form inner orbital octahedral complexes.

Question

Give the correct of initials T or F for following statements. Use T if statement is true and F if it is false.(I) $$Co(IIl)$$ is stabilised in presence of weak field ligands, while $$Co(II)$$ is stabilised in presence of strong field ligand.(II) Four coordinated complexes of $$Pd(II)$$ and $$Pt(II)$$ are diamagnetic and square planar.(III) $$Ni(CN)44$$− ion and $$Ni(CO)4$$ are diamagnetic tetrahedral and square planar respectively.(Iy) $$Ni2+$$ ion does not form inner orbital octahedral complexes.

Infinity Learn · Accepted Answer

(I) Both $$CO2+$$ and $$Co3+$$ are stabilized in the presence of strong field ligands due to higher CFSE values.  (II) Because of higher Zeff  value on the valence shell of $$Pd2+$$ and $$Pt2+$$ cations they, always from inner orbital complex. (III) $$Ni(CO)4$$;$$sp3$$, tetrahedral, μ$$=0BM$$           $$Ni(CN)44$$−; $$sp3$$, tetrahedral, μ$$=0BM$$       (IV) $$Ni2+$$ in the octahedral field.  ⇒ i.e., electronic distribution remains unaffected.

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