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Q.

Give the products of the following reactions, I. Li+N2⟶Δ II. Mg+N2⟶Δ III. N2(g)+H2(g)→773 K Here, I, II and III refer to

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a

I - Li2N ; II - Mg3N2 ; III - NH3

b

I - Li2N ; II - Mg3N ; III - NH3

c

I - Li3N ; II - Mg3N ; III - 2NH3

d

I - 2Li3N ; II - Mg3N2 ; III - 2NH3(g)

answer is D.

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Detailed Solution

6Li+N2→Heat2Li3N3Mg+N2→HeatMg3N2N2(g)+3H2(g)⇌773 K2NH3(g) ;ΔfH∘=−46.1 kJ mol−1

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