Q.

Given below are the half-cell reactions, Mn2++2e−⟶Mn;E∘=−1.18eV2Mn3++e−⟶Mn2+;E∘=+1.51eVThe E∘ for 3Mn2+⟶Mn+2Mn3+ will be

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-2.69 V, the reaction will not occur

-2.69 V, the reaction will occur

-0.33 V, the reaction will not occur

-0.33 V, the reaction will occur

answer is A.

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Detailed Solution

If Ecello is positive, reaction is spontaneous, otherwise it is non-spontaneous. Mn2++2e−⟶Mn;E∘=−1.18V 2Mn2+⟶2Mn3++2e−;E∘=−1.51V 3Mn2+⟶Mn+2Mn+3 E∘=Eoxi∘+Ered∘=−1.51+(−1.18)=−2.69VNegative Ecello of the reaction indicates that reaction is non-spontaneous.

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