Given that C+2S→CS2 ∆H0f=+117.0 kJ mol-1 1 C+O2→CO2 ∆H0f=-393.0 kJ mol-1 2 S+O2→SO2 ∆H0f=-297.0 kJ mol-1 3 The heat of combustion of CS2 + 3O2 → CO2 + 2SO2 is
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a
-807 kJ mol-1
b
-1104 kJ mol-1
c
807 kJ mol-1
d
1104 kJ mol-1
answer is B.
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Detailed Solution
The required combustion equation is obtained as2 × eqn. 3 2S +2O2 →2SO2 2 × -297.0 kJ + eqn. 2 +C +O2 →CO2+ -393.0 kJ + eqn. 1 -C -2S →CS2+ +117.0 kJ or we get 2S +3O2 -2S → 2SO2 +CO2 -CS2 or CS2+ 3O2 → CO2+ 2SO2 -1104 kJ mol-1