Given $$C(s)$$ $$+$$ $$O2(g)$$ → $$CO2(g)$$; ΔH $$=$$ – $$395$$ $$KJS(s)$$ $$+$$ $$O2(g)$$ → $$SO2(g)$$; ΔH $$=$$ – $$295$$ $$KJCS2(l)$$ $$+3O2(g)$$ → $$CO2(g)$$ $$+$$ $$2SO2(g)$$; ΔH $$=$$ – $$1110$$ KJThe heat of foramation of $$CS2(l)$$ is

Question

Infinity Learn · Accepted Answer

.eq.(1) $$+2$$ eq.(2) $$-$$ eq (3)(eq$$. $$=$$ $$equation)        $$C(s)$$ $$+$$ $$O2(g)$$ → $$CO2(g)$$; Δ$$H1$$ $$=$$ – $$395$$ KJ     $$2S(s)$$ $$+2$$ $$O2(g)$$ →$$2$$ $$SO2(g)$$; Δ$$H2$$ $$=2($$ – $$295)$$ $$KJCO2(g)$$ $$+$$ $$2SO2(g)$$ →$$CS2(l)$$ $$+3O2(g)$$ ; Δ$$H3$$ $$=$$ $$+$$ $$1110$$ KJ                                                                                         $$C(s)$$ $$+$$ $$2S(s)$$ → $$CS2(l)$$ ;  ΔHf $$=$$ Δ$$H1$$ $$+$$ Δ$$H2$$ $$+$$ Δ$$H3$$                                         Δ$$Hf(CS2)$$  $$=$$ $$+125$$ $$KJ/mole$$

Given C(s) + O2(g) → CO2(g); ΔH = – 395 KJS(s) + O2(g) → SO2(g); ΔH = – 295 KJCS2(l) +3O2(g) → CO2(g) + 2SO2(g); ΔH = – 1110 KJThe heat of foramation of CS2(l) is

Start JEE / NEET / Foundation preparation at rupees 99/day !!

Detailed Solution

Get Expert Academic Guidance – Connect with a Counselor Today!