First slide

Electrochemical cell

Question

For the given cell, $Mg |{Mg}^{2 +} ∥ {Cu}^{2 +}| Cu$

Easy

A

Mg is cathode
B

Cu is cathode
C

The cell reaction is $Mg + {Cu}^{2 +} ⟶ {Mg}^{2 +} + Cu$
D

Cu is the oxidising agent

Solution

(i) Left side of cell represents oxidation half-cell i.e. oxidation of Mg and right side of cell represents reduction half-cell i.e. reduction of copper.
(ii) Cu is reduced and reduction occurs at cathode.
(iii) Mg is oxidised and oxidation occurs at anode.
(iv) Whole cell reaction can be written as

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