Q.
For the given cell, MgMg2+∥Cu2+Cu
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a
Mg is cathode
b
Cu is cathode
c
The cell reaction is Mg+Cu2+⟶Mg2++Cu
d
Cu is the oxidising agent
answer is A.
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Detailed Solution
(i) Left side of cell represents oxidation half-cell i.e. oxidation of Mg and right side of cell represents reduction half-cell i.e. reduction of copper.(ii) Cu is reduced and reduction occurs at cathode.(iii) Mg is oxidised and oxidation occurs at anode.(iv) Whole cell reaction can be written as
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