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Q.

For the given cell, MgMg2+∥Cu2+Cu

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a

Mg is cathode

b

Cu is cathode

c

The cell reaction is Mg+Cu2+⟶Mg2++Cu

d

Cu is the oxidising agent

answer is A.

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Detailed Solution

(i) Left side of cell represents oxidation half-cell i.e. oxidation of Mg and right side of cell represents reduction half-cell i.e. reduction of copper.(ii) Cu is reduced and reduction occurs at cathode.(iii) Mg is oxidised and oxidation occurs at anode.(iv) Whole cell reaction can be written as
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