Given CS2=0.120M,H2=0.10M,H2 S=0.20M and CH4=8.40×10-5M for the following reaction at 900o C, at eq. Calculate the equilibrium constant Kc CS2(g)+4H2(g)⇌CH4(g)+2H2 S(g)

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0.0120

0.0980

0.280

0.120

answer is C.

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Detailed Solution

kc=CH4H2 S2CS2H24=8.40×10-5×0.220.120×(0.1)4=0.280

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