Given ECr3+/Cr0=−0.72 V, EFe2+/Fe0=−0.42V . The potential for the cellCr|Cr3+0.1M||Fe2+0.01M|Fe

From the given representation of the cell, Ecell  can be found as follows.EcellEcell=E Fe2+/Fe0−ECr3+/Cr0−0.0596logCr3+2Fe2+3[nearest equation]=−0.42−(−0.72)−0.0596log(0.1)2(0.01)3=0.42+0.72−0.0596log0.1×0.10.01×0.01×0.01 =0.3−0.0596log10−210−6=0.3−0.0596×4=0.30−0.039=0.26V