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Given, ECr3+/Cro=−0.74V;     EMnO4−/Mn2+o=1.51 VECr2O72−/Cr3+o=1.33V;       ECl/Cl−o=1.36 V;Based on the data given above, strongest oxidizing agent will be

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a

Cl

b

Cr3+

c

Mn2+

d

MnO4−

answer is D.

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Detailed Solution

Higher the SRP (Standard Reduction Potential) stronger is the oxidizing agent. Among the given electrode potentials, EMnO4−/Mn2+o is highest. Hence, MnO4− is the strongest oxidizing agent.
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