Given ECr3+/Cr∘=0.74V;EMnO4−/Mn2+∘=1.51V ECr2O72−/Cr3+=1.33V;ECl/Cl−∘=1.36VBased on the data given above strongest oxidising agent will be

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Cr3+

Mn2+

MnO4−

answer is D.

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Detailed Solution

Higher the SRP, better the oxidising agent. Among the given EMnO4-/Mn2+o is highest, hence MnO4-is the strongest oxidising agent.

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