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Activity Series (OR) Electro chemicals series

Question

Given
$E_{{Mg}^{+ 2} / Mg}^{o} = - 2 .37 V; E_{{Cu}^{+ 2} / Cu}^{0} = + 0 .34 V; E_{{Mn}^{+ 2} / Mn}^{0} = - 1 .18 V$
${E^{0}}_{{Na}^{+} / Na} = - 2 .71 V$ Correct decreasing order of reducing power is

Moderate

A

Na > Mg > Mn > Cu
B

Cu > Mn > Mg > Na
C

Mg > Na > Mn > Cu
D

Na > Mg > Cu > Mn

Solution

Tendency to undergo reduction ${Na}^{+} < {Mg}^{+ 2} < {Mn}^{+ 2} < {Cu}^{+ 2}$
Oxidizing power of ${Na}^{+} < {Mg}^{+ 2} < {Mn}^{+ 2} < {Cu}^{+ 2}$
$∴$ Tendency to undergo oxidation will be Na> Mg > Mn > Cu
Reducing power of Na > Mg > Mn > Cu

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