Given that equilibrium constant for the reaction,2SO2(g)+O2(g) ⇌ 2SO3(g)has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature?SO3(g) ⇌ SO2(g)+12O2(g)

2SO2(g)+O2(g)⇌2SO3(g)Equilibrium constant for this reaction,K=SO32SO22O2-----(i)SO3(g)⇌SO2(g)+12O2(g)Equilibrium constant for this reaction isK'=SO2O21/2SO3--------(ii)On squaring both sides in Eq. (ii), we haveK'2=SO22O2SO32=1K=1278( as K=278)K'=1278=0.003597=5.99×10-2 or ≈6.0×10-2