(1) For the given heat of reaction,i) C(s)+O2(g)=CO2(g)+97kcal ii) CO2(g)+C(s)=2CO(g)−39kcalthe heat of combustion of CO(g) is:
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a
68 kcal
b
- 68 kcal
c
+48 kcal
d
None
answer is A.
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Detailed Solution
Subtracting equation (ii) from equation (i), we getC(s)+O2(g)=CO2(g)+97kcalCO2(g)+C(s)=2CO(g)−39kcal--------------------------------------------------- or −CO2(g)+O2(g)=CO2(g)−2CO(g)+136kcal or 2CO(g)+O2=2CO2(g)+136kcal or, CO(g)+12O2(g)=CO2(g)+68kcalRequired value : 68 kcal.