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Q.

Given: r = R0A⅓, where r is the radius of nucleus of mass no. A and R0 is a constant whose value is equal to 1.5 × 101-15 metre. (Given 1 amu = 1.66 × 10-15 g)What is the density of a nucleus of mass number A?

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a

43π1.5×10−153A

b

1.17×1017kg/cm3

c

1.17×10−17kg/m3

d

None of these

answer is B.

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Detailed Solution

r=R0A1/3∴ Volume of nucles (4/3)πr3=43π1.5×10−153m3 density d=mV=1.66×10−27kg4/3×3.141.5×10−153=1.17×1017kg/m3
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