In the given reaction,            2Cu+(aq)⇌Cu2+(aq)+Cu(s)ECu+/Cu∘=0.6V and ECu2+/Cu∘=0.41VFind out the equilibrium constant.

Right hand cell reaction, Cu++e−⟶CuLeft hand cell reaction, Cu+⟶Cu2++e−Cell reactions, 2Cu+⟶Cu+Cu2+Cell potential Ecell ∘=ECu+/Cu∘−ECu2+/C∘                           =0.60−0.41=0.19V −nFE∘=−RTln⁡Keqlog⁡Keq=nE∘(2.303RT/F)=2×0.19V0.059V=6.44        Keq=106.44=2.76×106