In the given reaction, 2Cu+(aq)⇌Cu2+(aq)+Cu(s)ECu+/Cu∘=0.6V and ECu2+/Cu∘=0.41VFind out the equilibrium constant.

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2.76×102

2.76×104

2.76×106

2.76×108

answer is C.

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Detailed Solution

Right hand cell reaction, Cu++e−⟶CuLeft hand cell reaction, Cu+⟶Cu2++e−Cell reactions, 2Cu+⟶Cu+Cu2+Cell potential Ecell ∘=ECu+/Cu∘−ECu2+/C∘ =0.60−0.41=0.19V −nFE∘=−RTln⁡Keqlog⁡Keq=nE∘(2.303RT/F)=2×0.19V0.059V=6.44 Keq=106.44=2.76×106

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