Q.

Given the standard electrode potentials, K+/K=-2.93 V,Ag+/Ag=0.80 V,Hg2+/Hg=0.79 V Mg2+/Mg=-2.37 V Cr3+/Cr=-0.74 V Arrange these metals in their increasing order of reducing power.

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a

Ag

b

Ag

c

Ag

d

K

answer is C.

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Detailed Solution

More negative E° value means that the redox couple is a stronger reducing agent. The arrangement of metals in their increasing order of reducing power is as follows:Ag
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Given the standard electrode potentials, K+/K=-2.93 V,Ag+/Ag=0.80 V,Hg2+/Hg=0.79 V Mg2+/Mg=-2.37 V Cr3+/Cr=-0.74 V Arrange these metals in their increasing order of reducing power.