At a given temperature T, gases CO2, SiH4, SiF4 and O2 are found to deviate from ideal behaviour. Their equation of state is given as,p+aV2V=RT at T. Here ‘a’ van der Waals’ constant. Which gas will exhibit steepest decrease in plot of Z (compression factor) vs V−1?
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a
O2
b
CO2
c
SiH4
d
SiF4
answer is B.
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Detailed Solution
p+aV2V=RT⇒pV=RT−aV⇒Z=1−aRTVHigher the value of ‘a’, higher is the slope. Value of ‘a’ depends on intermolecular forces of attraction. Among the given non-polar gases SiF4 should have the highest value of ‘a’.