First slide

Glucose

Question

$Glucose \overset{X}{\to} n - hexane;$ ‘X’ in the reaction is

Easy

A

$HCN$
B

${NH}_{2} OH$
C

${LiAlH}_{4}$
D

$HI + Red P / 150^{0} c$

Solution

$HI + Red P / 150^{0} c$ can reduce
$(a) - OH \to - H; (b) - CHO \to - {CH}_{3}; (c) - CO - \to - {CH}_{2} -; (d) - COOH \to - {CH}_{3}; Thus OHC - {(CHOH)}_{4} - {CH}_{2} OH \to H_{3} C - {({CH}_{2})}_{4} - {CH}_{3};$

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