10 gm of a gas at 1atm and 273 K occupies 5 liters. The temperature at which the volume becomes double for the same mass of gas at the same pressure is:
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a
273 K
b
−273∘C
c
273∘C
d
546∘C
answer is C.
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Detailed Solution
V1T1=V2T2Volume is doubled when Temperature is doubled.Hence T2 = 546K = 273oc