$$6.8$$ gm of $$H2O2$$ is present in $$500$$ ml of an aqueous solution. When $$10ml$$ of this solution is decomposed, what is the S.T.P. volume of oxygen obtained

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M $$=$$ $$0.4Mvolume$$ strength $$=$$ M x $$11.2$$                       $$=$$ $$0.4$$ x $$11.2$$                       $$=$$ $$4.484.48$$ volume strength of $$H2O2$$ $$means1ml$$ of $$H2O2$$ solution gives → $$4.48ml$$ of,$$O210ml$$ of $$H2O2$$ solution gives → ??ml  of $$O2Therefore$$ $$10ml$$, $$4.48(W/V$$%$$)$$ volume strength of $$H2O2$$ solution gives $$44.8ml$$ of $$O2$$ at STP.

6.8 gm of H₂O₂ is present in 500 ml of an aqueous solution. When 10ml of this solution is decomposed, what is the S.T.P. volume of oxygen obtained

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6.8 gm of H2O2 is present in 500 ml of an aqueous solution. When 10ml of this solution is decomposed, what is the S.T.P. volume of oxygen obtained

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6.8 gm of H₂O₂ is present in 500 ml of an aqueous solution. When 10ml of this solution is decomposed, what is the S.T.P. volume of oxygen obtained