245 gram of KClO3 on decomposition produce 2.4 gram of O2 .What is % purity of KClO3?

Gram molecular weight of KClO3=39+35.5+48=122.5 gram/mole 2KClO3→2KCl+3O2According to equation 245 gram of KClO3 should produce 3×32=96 gram of O2 if KClO3 is 100 % pure.96 gm of O2 is produced when KClO3 is 100 percent pure.When 2.4 gm of O2 is produced , the percentage purity is 10096×2.4 = 2.5