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18 grams of Aluminium is heated with 8 grams of Oxygen to form Alumina. The weight of excess reagent left is
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a
9 grams of Aluminium
b
4.16 grams of Oxygen
c
10.08 grams of Oxygen
d
4.5 grams of Aluminium
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Correct option is A
GEW of Al = 9 gGEW of O2= 8 g;8 grams of Oxygen require 9 grams of Al.Weight of Al left = 9 g ;Alternate method:4Al4×27 g + 3O23×32 g → 2Al2O3 X g 8 g X= 8×4×273×32=9 g ; Weight of excess Al =18-9 g=9 g ;
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