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Q.

3.9 grams of Benzene is burnt in 2.24mL of oxygen at suitable conditions to form carbon di oxide and water?C6H6+152O2→6CO2+3H2OLimiting reagent in the above reaction isThe amount of reactant left over after the completion of the reaction is(approx)The volume in mL of carbon di oxide formed is

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a

Oxygen

b

Benzene

c

Catalyst

d

Both are consumed in 1:1 ratio

e

3.8

f

2.8

g

1.8

h

0.8

i

0.05

j

0.5

k

5

l

50

answer is , , .

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Detailed Solution

3.978=2.2422400×215 0.05: 0.0000133The above is ratio of Benzene : Oxygenwt of benzene78=0.00001330.0000133 =vol22400×6
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