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Q.

40 grams of CaCO3 is allowed to dissociate in a 11.2 litres container at 8190C .  If 50% of CaCO3 is dissociated at equilibrium the ' Kp ' value is

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a

5atm

b

1.6atm

c

4.8atm

d

10atm

answer is B.

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Detailed Solution

CaCO3→Cao+CO2(g) 40g               0       0        Initial 20g                          0.2molPV=nRT P=nRTV =0.2×0.0821×109211.2 =1.6atmKp=PCO2 KP=1.6atm
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