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50 grams of calcite on thermal decomposition yielded 21grams of quicklime . Percentage yield of the product is

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answer is 3.

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Detailed Solution

CaCO3(s)→CaO(s) + CO2(g) 100g 56g 50g ? = 28g But amount of quicklime obtained = 21gPercentage yield of product = 2128×100 = 75%

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