34 grams Iodo propane is treated with alcoholic KOH. What mass of propene is obtained if yield of the product is 50%(AW of Iodine=127)

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Detailed Solution

C3H7I + KOHalc→CH3CH=CH2+KI+H2O; 170 g 42 g 34 g ? Propene formed when the yield is 100%= 42×34170=8.4gm; Since the yield is 50% , propene formed =8.4×0.5=4.2 gm

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