50 grams of lime stone on calcination liberated 16.5 grams of carbon dioxide. Percentage yield of carbon dioxide is equal to

CaCO3s →∆ CaOs+CO2g;  100 g                                    44 g    50 g                                    22 g ; If the yield is 100% then the weight of CO2 liberated =22 g ; but the weight of CO2 obtained is 16.5 g; Thus percentage yield of CO2=16.522×100=75% ;