Q.
10 grams of limestone on calcination liberates 1.68 lit of CO2 at STP. Percentage purity of limestone is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
CaCO3S → CaOs + CO2g100 g 22.4 lit10 g 2.24 lit 10 grams of 100% pure limestone liberates 2.24 lit CO2 of at STP10 grams of “X%” pure limestone liberates 1.68 lit of CO2 at STPPercentage purity (X) = 1.682.24 × 100 = 75 %
Watch 3-min video & get full concept clarity