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Stoichiometry and Stoichiometric Calculations
Question

10 grams of limestone on calcination liberates 1.68 lit  of CO2 at STP. Percentage purity of limestone is

Moderate
Solution

CaCO3S   CaOs  +  CO2g

100 g                                                     22.4 lit

10 g                                                        2.24 lit    

10 grams of 100% pure limestone liberates 2.24 lit CO2 of  at STP

10 grams of “X%” pure limestone liberates 1.68 lit of CO2  at STP

Percentage purity  (X)  = 1.682.24  ×  100

                                                = 75 %

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