First slide

Methods to find equivalent weight

Question

20 grams of metal carbonate on calcination gives 11.2 grams of metal oxide. Atomic weight of the bivalent metal is

Moderate

A

40
B

50
C

100
D

20

Solution

$\frac{W_{metal carbonate}}{W_{metal oxide}} = \frac{E_{metal carbonate}}{E_{metal oxide}}; \frac{W_{metal carbonate}}{W_{metal oxide}} = \frac{E_{M} + E_{carbonate}}{E_{M} + E_{oxide}}; \frac{20}{11.2} = \frac{E + 30}{E + 8}; E = 20; AW = EW \times Valency; AW = 20 \times 2 = 40;$

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