6.90 grams of metal carbonate was completely decomposed by 50 ml of 2N HCl. The equivalent weight of metal is
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a
39
b
45
c
72
d
52
answer is A.
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Detailed Solution
NV(inml)1000=Wt of metalcarbonateeq.wt of metal carbonate50×21000=6.90eq.wt of metal carbonate∴ eq.wt of metal carbonate = 6.90 x 10 = 69Eq.wt of metal +Eq.wt of carbonate = 69Eq.wt of metal + 30 = 69Eq.wt of metal= 69 – 30 = 39