9.2 grams of N2O4( g) is taken in a closed one liter vessel and heated till the following equilibrium is reached N2O4(g)⇌2NO2(g) At equilibrium, 50% N2O4(g) is dissociated. What is the equilibrium constant (in mol litre-1) (molecular weight of N2O4=92

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0.1

0.4

0.2

answer is C.

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Detailed Solution

N2O4(g)⇌2NO2(g) t=0, 0.1M 0 teq., 0.1(1-α) 2(0.1α) ∵α=0.5 kc=NO22 N2O4=2×5×10-225×10-2=0.2

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