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Q.

5.3 grams of  Na2CO3 is dissolved  in 200ml of a solution. It is diluted by adding 800 ml of water. 100ml of the resulting solution requires ‘V’ ml of 0.02N H2SO4 solution for complete neutralization. ‘V’ is

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answer is 3.

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Detailed Solution

i)   N = 5.353×1000200     N = 0.5Nii)  V1N1 = V2N2     2000.5 = 200+800N2    N2 = 0.1Niii) VbNb = VaNa    1000.1 = Va0.02     Va = 500ml
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