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0.6 grams of an organic compound in Kjeldahl's method liberated ammonia. The liberated ammonia was absorbed using 100 ml of 0.1 M H2SO4 solution. The unreacted sulphuric acid required 80 ml of 0.1 M caustic soda for complete neutralization. The percentage of nitrogen in the organic compound is

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Detailed Solution

Volume of H2SO4neutralized by NaOH = ?Va'Na(H2SO4)=VbNb(NaOH) Va'(0.1)2=80(0.1)1 Va'=40 ml VH2SO4(initial)=100 ml; VH2SO4  neutralized by NH3=100-40 ml=Va Percentage of Nitrogen =1.4×Va×NaWOc=1.4×60×0.20.6=28%
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0.6 grams of an organic compound in Kjeldahl's method liberated ammonia. The liberated ammonia was absorbed using 100 ml of 0.1 M H2SO4 solution. The unreacted sulphuric acid required 80 ml of 0.1 M caustic soda for complete neutralization. The percentage of nitrogen in the organic compound is