60 grams of sodium hydroxide is required to completely neutralize 49 grams of sulphuric acid, percentage purity of sodium hydroxide sample is

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66.6%

33.3%

54%

90%

answer is A.

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Detailed Solution

2NaOH + H2SO4→Na2SO4+2H2O ; 2×40g 98g 80 grams of pure NaOH is required to neutralize 98 grams of H2SO4; 40 grams of pure NaOH is required to neutralize 49 grams of H2SO4; But in the given question, 60 grams of NaOH was required; Percentage purity of NaOH=4060×100=66.6%

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