Questions
60 grams of sodium hydroxide is required to completely neutralize 49 grams of sulphuric acid, percentage purity of sodium hydroxide sample is
Remember concepts with our Masterclasses.
80k UsersReady to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is A
2NaOH + H2SO4→Na2SO4+2H2O ; 2×40g 98g 80 grams of pure NaOH is required to neutralize 98 grams of H2SO4; 40 grams of pure NaOH is required to neutralize 49 grams of H2SO4; But in the given question, 60 grams of NaOH was required; Percentage purity of NaOH=4060×100=66.6%Talk to our academic expert!
Create Your Own Test
Your Topic, Your Difficulty, Your Pace
Similar Questions
The weight of iron which will be converted into its oxide ( ) by the action of 18 g of steam on it will be (Atomic weight of Fe = 56)
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
