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Q.

0.5grams of a week base BOH present in 50ml solution is titrated with 0.1M HCl. The pH at half - neutralization is found to be ‘9’ and the pH at equivalence point is found to be 5.15. The equivalence conductance of BOH at infinite dilution is 400 S.cm2 eq-1. If the specific conductance of initial BOH (before titration) solution is x×10−4 Scm−1, what is the value of ‘x’

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Detailed Solution

Δtfα molality of particles of solute Δtf expected =0.2×1.86Δtf actual =0.37944Molality of particles after hydrolysis = 0.2+x0.379440.2×1.86=0.2+x0.2x=0.204−0.2=0.004 % hydrolysis=4
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0.5grams of a week base BOH present in 50ml solution is titrated with 0.1M HCl. The pH at half - neutralization is found to be ‘9’ and the pH at equivalence point is found to be 5.15. The equivalence conductance of BOH at infinite dilution is 400 S.cm2 eq-1. If the specific conductance of initial BOH (before titration) solution is x×10−4 Scm−1, what is the value of ‘x’