Graph between log xm and log p is a straight line inclined at an angle of 45° and log k 0.6990 for Freundlich's adsorption isotherm. xm is the amount of adsorbate adsorbed per gram of the adsorbent]. What is the value of xm at 0.80 atm?
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answer is 4.
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Detailed Solution
For Frendlich's adsorption isotherm xm=k(p)1/n∴ logxm=1nlogp+logky mx + C It represents a straight line.Intercept OA 0.6990logk=0.6990=log51x=tanθ=tan45∘=1∴ logxm=log(0.8)+log5=log(0.8×5)=log4xm=4
Graph between log xm and log p is a straight line inclined at an angle of 45° and log k 0.6990 for Freundlich's adsorption isotherm. xm is the amount of adsorbate adsorbed per gram of the adsorbent]. What is the value of xm at 0.80 atm?