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Graph between log xm and log p is a straight line inclined at an angle of 45° and log k 0.6990 for Freundlich's adsorption isotherm. xm is the amount of adsorbate adsorbed per gram of the adsorbent]. What is the value of xm at 0.80 atm?

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answer is 4.

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Detailed Solution

For Frendlich's adsorption isotherm xm=k(p)1/n∴ log⁡xm=1nlog⁡p+log⁡ky mx + C It represents a straight line.Intercept OA 0.6990log⁡k=0.6990=log⁡51x=tan⁡θ=tan⁡45∘=1∴ log⁡xm=log⁡(0.8)+log⁡5=log⁡(0.8×5)=log⁡4xm=4
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