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Q.

Graph between log x/m and log p is a straight line inclined at an angle of 45o. When pressure is 0.5 atm and In k = 0.693, the amount of solute adsorbed per gram of adsorbent will be:

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a

1

b

1.5

c

0.25

d

2.5

answer is A.

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Detailed Solution

log⁡xm=log⁡k+1nlog⁡p1n=tan⁡45o,     ln⁡k=0.693n=1                 log⁡k=0.3log⁡xm=0.3+log⁡(0.5)log⁡xm=0.3−0.3=0xm=10o=1
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