Graphically variation of log10 p with 1/T is shown. If tan θ (slope of the line) = - 2K, Iatent heat of vaporisation of the given liquid is
2.303calmol−1
4.606calmol−1
9.212 cal mol−1
4.00calmol−1
Variation of log10 p with 1T given by Clausius-Clapeyron I equation (linear equation)
log10p=−ΔH2.303RT+A
slope −ΔH2.303R=−2 (given)
∴ ΔH=2.303R×2
=2.303×2×2=9.212calmol−1