Q.

Graphically variation of log10 p with 1/T is shown. If tan θ (slope of the line) = - 2K, Iatent heat of vaporisation of the given liquid is

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a

2.303calmol−1

b

4.606calmol−1

c

9.212 cal mol−1

d

4.00calmol−1

answer is C.

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Detailed Solution

Variation of log10 p with 1T given by Clausius-Clapeyron I equation (linear equation)log10p=−ΔH2.303RT+A slope −ΔH2.303R=−2 (given) ∴ ΔH=2.303R×2=2.303×2×2=9.212calmol−1
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