Graphically variation of log10 p with 1/T is shown. If tan θ (slope of the line) = - 2K, Iatent heat of vaporisation of the given liquid is

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

2.303calmol−1

4.606calmol−1

9.212 cal mol−1

4.00calmol−1

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Variation of log10 p with 1T given by Clausius-Clapeyron I equation (linear equation)log10p=−ΔH2.303RT+A slope −ΔH2.303R=−2 (given) ∴ ΔH=2.303R×2=2.303×2×2=9.212calmol−1

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET