First slide

Group 14 or carbon family

Question

In graphite and diamond, the percentage of p- characters of the hybrid orbitals involved in hybridisation are respectively ___?

Moderate

A

33 and 25
B

67 and 75
C

50 and 75
D

33 and 75

Solution

In graphite , carbon atom under go ' $s p^{2}$ 'Hybridisation
In diamond, carbon atom undergo $s p^{3}$ Hybridisation
$% of p character in graphite (s p^{2}) = \frac{2}{3} \times 100 = 67 %$
$% of p character in diamond (s p^{3}) = \frac{3}{4} \times 100 = 75 %$

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