A green plant contains radioactive C 14 and C 12 isotope. If in a sample of dead old wood of this plant 2.5×10-6 mol14C and 7.5×10-6 mol14 N are present then calculate value of Z. Assuming all ‘N’ is obtained due to disintegration of 14C.Where Z=Age of woodtHalf life of 14C isotopet1/2

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answer is 2.

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Detailed Solution

614C→ 714N+70e∧t=ln N0Nt=ln10×10−62.5×10−6=ln 4ln 2t1/2t=2 ln 2t=2 t1/2z=2

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