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Q.

The ground state energy of hydrogen atom is –13.6 eV. Calculate the energy of second excited state of He+ ion in eV.

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answer is -6.04.

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Detailed Solution

According to Bohr’s model energy in nth state =-13.6×Z2n2eV For second excited state, of He+, n = 3∴E3He+=-13.6×2232eV=-6.04eV
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