Q.
The ground state energy of hydrogen atom is -13.6 eV. The Energy of second exited state of He+ ion in eV is
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a
-54.4
b
-6.04
c
-3.4
d
-27.2
answer is B.
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Detailed Solution
E3He+=−13.6×z2n2eV=−13.6×2232eV=−6.04eV
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