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Q.

The ground state energy of hydrogen atom is -13.6 eV. The Energy of second exited state of He+ ion in eV is

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a

-54.4

b

-6.04

c

-3.4

d

-27.2

answer is B.

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Detailed Solution

E3He+=−13.6×z2n2eV=−13.6×2232eV=−6.04eV
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The ground state energy of hydrogen atom is -13.6 eV. The Energy of second exited state of He+ ion in eV is