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The ground state energy of hydrogen atom is -13.6 eV. The Energy of second exited state of ${He}^{+}$ ion in eV is

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-54.4

-6.04

-3.4

-27.2

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detailed solution

Correct option is B

E3He+=−13.6×z2n2eV=−13.6×2232eV=−6.04eV

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The ground state energy of hydrogen atom is -13.6 eV. The Energy of second exited state of He+ ion in eV is

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Ready to Test Your Skills?

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The ground state energy of hydrogen atom is -13.6 eV. The Energy of second exited state of ${He}^{+}$ ion in eV is