H3AsO3+I2+H2O=H3AsO4+2HI 0.01 equivalent of the mentioned acid will neutralize how manygrams of NaOH?
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answer is 0.40.
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Detailed Solution
H3As+3O3+I2+H2O=H3As+5O4+2HI ∴ x 2 ∴ Equiv. wt. of H3AsO3= Mol. wt. of H3AsO32=1262=63 ∴0.01 equiv. of H3AsO3=0.63gH3AsO3H3AsO3+2NaOH=Na2HasO3+2H2O 126gH3AsO3 reacts with 80g of NaOH 0.63gH3AsO3 reacts with 80126×0.63g of NaOH = 0.4 g of NaOH.