First slide

Hydrogen

Question

${}_{1}^{1}H, {}_{1}^{2}H and {}_{1}^{3}H$ differ in number of

Easy

A

electrons
B

protons
C

neutrons
D

positrons

Solution

${}_{1}^{1}H \to 1 e^{-}, 1 p, no n$
${}_{1}^{2}H \to 1 e^{-}, 1 p, 1 n$
${}_{1}^{3}H \to 1 e^{-}, 1 p, 2 n$

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