$$H2O2$$ acts as both oxidising and reducing agent. As oxidising agent, its product is $$H2Obut$$ as reducing agent, its product is $$O2$$. Volume strength has great significance for chemical reactions. The strength of ‘$$10V$$’ means $$1$$ volume (or$$ $$liter) of $$H2O2$$ on decomposition (H2O2$$→ $$H2O$$ $$+$$ $$12$$ $$O2) gives $$10$$ volumes (or$$ $$liter) of oxygen at $$NTP.15$$ g $$Ba(MnO4)2$$ sample containing inert impurity is completely reacting with $$100$$ mL of ‘$$11.2$$ V’ $$H2O2$$, then what will be the % purity of $$Ba(MnO4)2$$ in the sample : (Atomic$$ mass : Ba $$=$$ $$137$$, Mn $$=$$ $$55)

Question

$$H2O2$$ acts as both oxidising and reducing agent. As oxidising agent, its product is $$H2Obut$$ as reducing agent, its product is $$O2$$. Volume strength has great significance for chemical reactions. The strength of ‘$$10V$$’ means $$1$$ volume (or$$ $$liter) of $$H2O2$$ on decomposition (H2O2$$→   $$H2O$$ $$+$$ $$12$$ $$O2) gives $$10$$ volumes (or$$ $$liter) of oxygen at $$NTP.15$$ g $$Ba(MnO4)2$$ sample containing inert impurity is completely reacting with $$100$$ mL of ‘$$11.2$$ V’ $$H2O2$$, then what will be the % purity of $$Ba(MnO4)2$$ in the sample : (Atomic$$ mass : Ba $$=$$ $$137$$, Mn $$=$$ $$55)

Infinity Learn · Accepted Answer

$$Ba(MnO4)2+5H2O2+3H2SO4$$→$$BaSO4+2MnSO4+5O2+8H2Omilliequivalents$$ of $$Ba(MnO4)2$$ reacted $$=$$ milliequivalents of $$H2O2$$ reactedmE×$$1000=NV(ml)$$      ; $$EBa(MnO4)2$$  $$=37510$$  ; $$NH2O2$$ $$=vol$$.$$strength5.6$$ $$m375$$ ×  $$10$$ ×  $$1000=11.25.6$$ × $$100$$∴   $$m=7.5$$  g∴    wt.  of  $$BaMnO42$$  in  sample  $$=$$  $$7.5$$  g%  purity  of  $$BaMnO42$$  in  sample  $$=$$ $$7.515$$  ×  $$100=50$$%

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