First slide

Hydrogen Peroxide

Question

$H_{2} O_{2}$ can be obtained when following reacts with $H_{2} {SO}_{4}$ except with

Moderate

A

${PbO}_{2}$
B

${BaO}_{2}$
C

${Na}_{2} O_{2}$
D

${SrO}_{2}$

Solution

${BaO}_{2} + dil . H_{2} {SO}_{4} \to {BaSO}_{4} + H_{2} O_{2} {Na}_{2} O_{2} + dil . H_{2} {SO}_{4} \to {Na}_{2} {SO}_{4} + H_{2} O_{2} {SrO}_{2} + dil . H_{2} {SO}_{4} \to {SrSO}_{4} + H_{2} O_{2} {PbO}_{2} + dil . H_{2} {SO}_{4} \to {PbSO}_{4} + H_{2} O + \frac{1}{2} O_{2} ↑ {PbO}_{2} + H_{2} {SO}_{4} cannot give H_{2} O_{2}, instead of it gives H_{2} O + \frac{1}{2} O_{2} ↑$

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