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Q.

2H2O⇌H3O++OH−Kw=1×10−14 at 25∘C. Hence, Ka is

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a

1×10−14

b

5.55×10−13

c

1.8×10−16

d

1.00×10−7

answer is C.

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Detailed Solution

Kw=H+OH−=1×10−14 ∴ H+=1×10−7M C=1g/mL=1000g/L =55.55M Also, in weak acid, H′=KaC ∴ Ka=H+2C=10−1455.55=1.8×10−16

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