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Q.

2H2O  ⇌   H3O+ + OH-Kw = 1 × 10-14  at  250C. Hence, Ka is

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a

1 × 10-14

b

5.55 × 10-13

c

1.8 × 10-16

d

1.00 × 10-7

answer is C.

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Detailed Solution

Kw = H+ OH-= 1 × 10-14 ∴   H+ = 1 × 10-7 M, density of water = 1 g / mL  ; or 1000 g/L    C=number of moles(n)/lit   =  1000/18 =  55.55 MAlso in weak acid H+  = KaC∴   Ka = H+2C = 10-1455.55=1.8 × 10-16
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