2H2O ⇌ H3O+ + OH-Kw = 1 × 10-14 at 250C. Hence, Ka is
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a
1 × 10-14
b
5.55 × 10-13
c
1.8 × 10-16
d
1.00 × 10-7
answer is C.
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Detailed Solution
Kw = H+ OH-= 1 × 10-14 ∴ H+ = 1 × 10-7 M, density of water = 1 g / mL ; or 1000 g/L C=number of moles(n)/lit = 1000/18 = 55.55 MAlso in weak acid H+ = KaC∴ Ka = H+2C = 10-1455.55=1.8 × 10-16